Методы интегрирования. Распутько Т.Б - 32 стр.

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УлГТУ | Ульяновск

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32
14.
xx
39
cossin ⋅
4
b 0,a ,
2
sin
4
π
==
x
xx 4sin8sin ⋅
15.
x
x
6
3
cos
sin
4
b 0,a ,
2
cos
4
π
==
x
xx 5coscos ⋅
16.
xx
93
cossin ⋅
3
b 0,a ,cossin
22
π
==⋅ xx
xx 9cos3sin ⋅
17.
xx
312
cossin ⋅
3
b 0,a ,
2
cos
2
sin
22
π
==⋅
xx
xx 5sin7sin ⋅
18.
x
x
8
5
sin
cos
3
2
b 0,a ,
4
cos
4
sin
22
π
==⋅
xx
xx 6cos3cos ⋅
19.
xx
103
cossin ⋅
3
b 0,a ,sin
4
π
==x
xx 7cos3sin ⋅
20.
xx
58
cossin ⋅
3
b 0,a ,
2
sin
4
π
==
x
xx 4sin5sin ⋅
21.
x
x
2
5
cos
sin
12
5
b 0,a ,cossin
22
π
==⋅ xx
xx 2cos10cos ⋅
22.
xx
75
cossin ⋅
12
5
b 0,a ,
2
cos
2
sin
22
π
==⋅
xx
xx 11cos5sin ⋅
23.
xx
38
cossin ⋅
6
5
b 0,a ,
4
cos
4
sin
22
π
==⋅
xx
xx 2sin6sin ⋅
24.
x
x
6
5
sin
cos
12
5
b 0,a ,
2
cos
4
π
==
x
xx cos7cos ⋅
25.
xx
163
cossin ⋅
12
5
b 0,a ,
2
sin
4
π
==
x
xx 9cos4sin ⋅
26.
xx
54
cossin ⋅
4
3
b 0,a ,
2
sin
4
π
==
x
xx 6sin2sin ⋅
27.
x
x
10
3
cos
sin
12
7
b 0,a ,
2
cos
2
sin
22
π
==⋅
xx
xx 5cos3cos ⋅
28.
xx
25
cossin ⋅
6
7
b 0,a ,
4
cos
4
sin
22
π
==⋅
xx
xx 8cos2sin ⋅
29.
xx
36
cossin ⋅
4
3
b 0,a ,
2
cos
4
π
==
x
xx 6sin4sin ⋅
30.
x
x
2
5
sin
cos
3
2
b 0,a ,
2
sin
4
π
==
x
xx 7cos3cos ⋅
Замена переменной
Задача 11.0 A)
∫
+
5
0
31 x
xdx
.
Положим
tx =+ 31 , тогда )1(
3
1
2
−= tx , tdtdttdx
3
2
)'
3
1
3
1
(
2
=−= ,
при х=0
1031 =⋅+=t , при х=5 4531 =⋅+=t .

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