Аналитическая геометрия. Часть I. Шурыгин В.В. - 22 стр.

        àxÿxXWxZ ­;= 30/2,-1 a=                               C
        —;**; −AF→ = −AC
                       → −→
                          + CF
                                               −→
                                             = AC +
1 −→ −→
2
  (AB − AC) =
                             1 −→ −→
                             2
                               (AB + AC)     = ˆ8/JL6             E
                                                                      F

,6N-L0; −→
        AE =
                             2 −→    1 −→ −→
                               AF = (AB + AC)        =   A                   B
                                                    Ç0/= a=
                             3       3


   ðÍwÍñÍ ÊZ ‡6, 83*2:-7?,01 ABC = €6M80 8-)12 O 8612J\ )8- −OA+
                                                              → −−→
                                                                  OB +
OC = 0 =
−→
                                   àxÿxXWxZ ­;= 30/2,-1 `= —;**;†
                               −−→ −→ −→ \ −→ −→ −→ H-~8-K
                               OB = OA + AB OC = OA + AC =
                    C
                                ;2 −OA  + OB + OC = 3OA + AB + AC 0\
                                     → −−→ −→         −→ −→ −→
                                /7*L-b68*7?,-\ −AO
                                                 →
                                                   = (AB + AC) = „610;
                                                      −→ −→
                                -+36[-;\ 2/7-b09; [6L6)0 2L-b7*8b-39*8
                                                                  1
                                                                  3
              O
 A                        B     -L,6 8-)16 · *,83 89|*/80 83*2:-7?,0K
           Ç0/= `=              16 ABC =
   ðÍwÍñÍ Z €6 b*18-36N −OA
                           → \ −−→ 0 −→ .-/83-*, .63677*7*.0.*L ‡-K
                                                                   =
        )                      OB OC
                                                            )
16[68?\ 8- L06:-,67? OD ~8-:- .63677*7*.0.*L6 .3-N-L08 *3*[ *,83
89|*/80 E 83*2:-7?,016 ABC =
                                       àxÿxXWxZ ­;= 30/2,-1 •^= H2/8? F
                                    · )*8b*3869 b*3I0,6 .63677*7*.0.*  K
      C      •                       •


                                    L6\ 7*|6}69 b .7-/1-/80 OAB = —;*K
•
             E     D     •
                             •
                                    *;† −OD
                                         −→    −→ −→ −−→
                                            = OA + AF + F D = OA +
                                                                  −→
            O        •                            −−→ −→ −−→       −→ −→       −→
                 •                       •        OB + OC, OE = OA + AE = OA +
                                         B        1 −→    −→      −→ 1 −→ −→
                                                    (AC + AB) =   OA + 3 (OC − OA +
                                                                                 „6K
                                                  3
                                                  −−→ −→       1 −→   −−→ −→
                                                  OB − OA) = 3 (OA + OB + OC).
        Ç0/= •^=                  10; -+36[-;\
    •                            •
A                   F
                                                       =      −−→ −−→
                                                              OE||OD
   ðÍwÍñÍ Z ‡-16[68?\ )8- /8-3-, AB 0 DC )*83*N2:-7?,016 ABCD
.63677*7?, 8-:L6 0 8-7?1- 8-:L6\ 1-:L6 -83*[-1 M N \ /-*L0,9J}0M /*K
3*L0, 0N /8-3-,\ .3-N-L08 )*3*[ 8-)12 O .*3*/*)*,09 L06:-,67*M=
   àxÿxXWxZ ­;= 30/2,-1 ••= Ç6//;-830; +6[0/ ,6 .7-/1-/80\ /-/8-9}0M
                                  ïï