Конспект лекций по статистической физике. Коренблит С.Э - 34 стр.

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                                    |34|
                     d 2s X
    â.¥. ¯® á¬ëá«ã: dE ) @E =)
                            * @ O (E )     I     jdj  G(E ); (3.32)
                                        H(X)=E jrX H (X )j
                          Z         Z         Z
         £¤¥: O(E )        dO        d X  d2s X (E H (X )); (3.33)
                                        2s
                    H(X)E      H(X)E       fX g
{ ¥áâì ¯®«­ë© ä §®¢ë© ®¡ê¥¬, ¤®áâã¯­ë© ª« áá¨ç¥áª®¬ã ­á ¬¡«î. ‚
í⮬ á«ãç ¥ 㦥 ­¥«ì§ï ®¤­®§­ ç­® ®¯à¥¤¥«¨âì í­âய¨î á ¯®¬®éìî
ä®à¬ã«ë ¢¨¤ (3.22): S =??) k ln O(E ), â ª ª ª O(E ) ï¥âáï à §¬¥à-
­®© ¢¥«¨ç¨­®©. ˆ¬¥­­® ­¥¢®§¬®¦­®áâì ¢ëç¨á«¨âì í­âய¨©­ãî ª®­-
áâ ­âã ï¥âáï ¯à¨­æ¨¯¨ «ì­ë¬ ­¥¤®áâ ⪮¬ ª« áá¨ç¥áª®£® áâ â¨áâ¨-
ç¥áª®£® ®¯¨á ­¨ï, ¨ á¢ï§ ­ , â ª¨¬ ®¡à §®¬, á ¯à®¡«¥¬®© \®¡¥§à §¬¥à¨-
¢ ­¨ï ®ç¥­ì ¡®«ì让 à §¬¥à­®áâ¨" hs ¤«ï ¢¥«¨ç¨­ ¢ (3.17){(3.20):
        (E ) = O(Es ) ; D(E; V ) = G(Es ) ; %(X ) = hs %cl (X ): (3.34)
                h                   h
ˆ­â¥£à « (3.32) ¨ \ᮡ¨à ¥â" (* )) ¢ (3.16){(3.21) á¬¥è ­­ë¥ ¬ˆªà®á®-
áâ®ï­¨ï ¯® á«®î dE ¢ ®¤­® ¬€ªà®á®áâ®ï­¨¥ á í­¥à£¨¥© E ¢ (3.18), (3.21).

4     ­âய¨ï ¨ ¢¥à®ïâ­®áâì
   „«ï ¬ˆªà®ª ­®­¨ç¥áª®£® à á¯à¥¤¥«¥­¨ï (3.21) á।­¥¥ §­ 祭¨¥ <>,
®ç¥¢¨¤­®, ¯à®á⮠ᮢ¯ ¤ ¥â á ­ ¨¡®«¥¥ ¢¥à®ïâ­ë¬ §­ 祭¨¥¬ E , ®â¢¥ç -
î騬 ¬ ªá¨¬ã¬ã ä㭪樨 W      g(E ). ᫨ ¢­®¢ì \à §¬ § âì" íâã ¤¥«ìâ -
äã­ªæ¨î, ¯¯à®ªá¨¬¨à®¢ ¢ ¥¥ 㧪¨¬ ¯àאַ㣮«ì­¨ª®¬ (3.18) (¢á¥ §­ ç¥-
­¨ï E ¢­ãâਠ­¥£® à ¢­®¢¥à®ïâ­ë) ¢ëá®â®© W        g(E ) ¨ è¨à¨­®© \à §¬ §ª¨"
E (E )  E , â®, ᮣ« á­® (3.2), (3.3), ¨§ (3.15), (3.18), (3.21) ¨¬¥¥¬ [20]:
          Z           Z
      1 = dW (E ) = W   g(E )dE =) W  g(E )E (E ) = w(E ) (E); (3.35)
      £¤¥:  (E )  (E; V ; E ) = D(E; V )E (E );                     (3.36)
{ áâ â¨áâ¨ç¥áª¨© ¢¥á â ª®£® à á¯à¥¤¥«¥­¨ï, ¥£® í­âய¨ï (3.23) à ¢­ :
                  S (E; V ) = k ln  (E ) =) k ln w(E ):               (3.37)
à¨ í⮬ ª®­áâ ­â C ¢ (3.20) ¯à¨®¡à¥â ¥â á¬ëá« á।­¥£® à ááâ®ï­¨ï
¬¥¦¤ã á®á¥¤­¨¬¨ ª¢ ­â®¢ë¬¨ ã஢­ï¬¨ á¨á⥬ë á í­¥à£¨¥© ¢¡«¨§¨ E :
                                     2           3
              E (E )                    S   E
      (E )   (E ) = E (E ) exp 4 k 5 = D(E;1 V ) = C:
                                           (   )
                                                                        (3.38)