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Рубрика:
27
()
()
()
()
()
()
⎪
⎪
⎪
⎩
⎪
⎪
⎪
⎨
⎧
=
=−
<
⇒
⎪
⎪
⎪
⎩
⎪
⎪
⎪
⎨
⎧
=
−=
=−=
зад
зад
зад
E
E
E
xF
xF
xF
2
1
2
1
0
2
1
'
2
1
'
01
2
1
*2'
1
3
1
2
1
1
2. По x
1
:
()
()
()
01*0110*
2
1
212'
11
)2()2(
2
1
12
1
=−−=−
⎟
⎠
⎞
⎜
⎝
⎛
−=−=
+
xx
xxF
αα
(
)
2
1
1*0
2
1
0
0'
12
1
)2(
2
1
1
=−=
=
=
+
x
xF
x
α
(
)
2
1
1*0
2
1
0
0'
12
1
)2(
2
1
1
=−=
=
=
+
x
xF
x
α
1.
По x
2
:
()
()
()
4
3
4
1
2
1
2
1
2
1
2
1
2
1
1
2
*
4
1
4
1
2
1
2
1
*
2
1
2
1
2
3
1
2
3
2
1
*
2
1
2'
12
2
)2(
)2()2(
)2()2()2(
12
2
2
22
222
=+=
⎟
⎠
⎞
⎜
⎝
⎛
−−=
==
−=
⎟
⎠
⎞
⎜
⎝
⎛
−
⎟
⎠
⎞
⎜
⎝
⎛
−
−=−+=−
⎥
⎦
⎤
⎢
⎣
⎡
⎟
⎠
⎞
⎜
⎝
⎛
−−=
+
+
x
xF
x
xx
xxx
α
αα
ααα
2.
По x
3
()
()
2
1
2
1
2
2
3
*2'
2
3
=−−=xF
27
⎧
⎧
⎪ F ' x1 ( )
(1)
= 2 *
1
2
− 1 = 0 ⎪0 < E
⎪ ⎪ зад
⎪
( )
(1)
⎨F ' x2 = −
1
2
⎪ 1
⇒ ⎨ − = E зад
⎪ ⎪ 2
⎪
( )
(1)
⎪ F ' x3 = 2
1 ⎪1
⎪ = E зад
⎩ ⎩2
2. По x1:
(
F ' x1
( 2 +1)
) = 2 x ( ) − 1 = 2⎛⎜ 12 − α
1
2 ( 2) ⎞
* 0 ⎟ − 1 = 1 − 0 *α ( 2) x − 1 = 0
⎝ x1
⎠ 1
( )
F ' x1 = 0
2
α ( 2) x = 0
1
2 +1 1 1
x1 = − 0 *1 =
2 2
( )
F ' x1 = 0
2
α ( 2) x = 0
1
2 +1 1 1
x1 = − 0 *1 =
2 2
1. По x2:
(
F ' x2
( 2 +1)
) = ⎡⎢2 12 − α ( 2) ⎛ 1 ⎞⎤ 3 3
* ⎜ − ⎟⎥ − = 1 + α ( 2 ) x − = α ( 2 ) x −
1
⎣
x2
⎝ 2 ⎠⎦ 2 2 2 2 2
⎛ 1 ⎞ ⎛ ( 2) 1 ⎞ 1 ( 2) 1
⎜ − ⎟ * ⎜ α x2 − ⎟ = α x2 −
⎝ 2⎠ ⎝ 2⎠ 2 4
1 2 1
α ( 2) x = * =
2 4 1 2
( 2 +1) 1 1⎛ 1⎞ 1 1 3
x2 = − ⎜− ⎟ = + =
2 2⎝ 2⎠ 2 4 4
2. По x3
( ( ) ) = 2 * 32 − 2 − 12 = 12
F ' x3
2
