Интегральное исчисление. Определенный интеграл - 47 стр.

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F (x) = arctg
1
x
x = 0 [1, 1]
f(x) =
1
1 + x
2
f(x) =
1
1 + x
2
[1, 1] Φ(x) = arctg x
1
Z
1
dx
1 + x
2
= arctg x
¯
¯
¯
¯
1
1
= arctg 1 arctg(1) =
π
4
³
π
4
´
=
π
2
.
lim
x→−0
arctg
1
x
=
π
2
lim
x+0
arctg
1
x
=
π
2
F
1
(x) =
arctg
1
x
, 1 x < 0,
π
2
, x = 0,
F
2
(x) =
arctg
1
x
, 0 < x 1,
π
2
, x = 0,
[1, 0] [0, 1]
1
Z
1
dx
1 + x
2
=
0
Z
1
dx
1 + x
2
+
1
Z
0
dx
1 + x
2
= F
1
(x)
¯
¯
¯
¯
0
1
+F
2
(x)
¯
¯
¯
¯
1
0
=
=
µ
π
2
¡
arctg(1)
¢
+
µ
arctg 1
³
π
2
´
=
π
2
.