Интегрирование функций одного переменного: примеры и задачи. Ч.1. Неопределенный интеграл: основные понятия, свойства, методы интегрирования. Кропотова Т.В - 72 стр.

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ch(a ± b) = ch a ch b ± sh a sh b;
sh(a ± b) = sh a ch b ± ch a sh b;
th(a ± b) =
th a ± th b
1 ± th a th b
;
cth(a ± b) =
cth a cth b ± 1
cth b ± cth a
.
ch 2a = ch
2
a + sh
2
a; sh 2a = 2 sh a ch a;
th 2a =
2 th a
1 + th
2
a
; cth 2a =
1 + cth
2
a
2 cth a
.
ch a + ch b = 2 ch
a + b
2
ch
a b
2
;
ch a ch b = 2 sh
a + b
2
sh
a b
2
;
sh a + sh b = 2 sh
a + b
2
ch
a b
2
;
sh a sh b = 2 sh
a b
2
ch
a + b
2
;
th a ± th b =
sh(a ± b)
ch a ch b
; cth a ± cth b =
sh(b a)
sh a sh b
.
ch a ch b =
1
2
h
ch(a + b) + ch(a b)
i
;
sh a sh b =
1
2
h
ch(a + b) ch(a b)
i
;
sh a ch b =
1
2
h
sh(a + b) + sh(a b)
i
.
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     3. Ôîðìóëû ñëîæåíèÿ àðãóìåíòîâ.

                  ch(a ± b) = ch a ch b ± sh a sh b;
                  sh(a ± b) = sh a ch b ± ch a sh b;
                                   th a ± th b
                      th(a ± b) =               ;
                                  1 ± th a th b
                                  cth a cth b ± 1
                    cth(a ± b) =                  .
                                   cth b ± cth a
     4. Ôîðìóëû äâîéíîãî àðãóìåíòà.

         ch 2a = ch2 a + sh2 a;   sh 2a = 2 sh a ch a;
                    2 th a               1 + cth2 a
          th 2a =           ;   cth 2a =            .
                  1 + th2 a                2 cth a
  5. Ôîðìóëû ñëîæåíèÿ îäíîèìåííûõ ãèïåðáîëè÷åñêèõ ôóíê-
öèé.

                                        a+b a−b
                     ch a + ch b = 2 ch      ch       ;
                                         2         2
                                        a+b a−b
                     ch a − ch b = 2 sh      sh       ;
                                         2         2
                                        a+b a−b
                     sh a + sh b = 2 sh      ch       ;
                                         2        2
                                        a−b a+b
                     sh a − sh b = 2 sh      ch       ;
                                         2         2
                         sh(a ± b)                     sh(b ∓ a)
          th a ± th b =             ; cth a ± cth b =             .
                          ch a ch b                     sh a sh b
     6. Ôîðìóëû ïðåîáðàçîâàíèÿ ïðîèçâåäåíèÿ â ñóììó.
                              1h                    i
                   ch a ch b = ch(a + b) + ch(a − b) ;
                              2
                              1h                    i
                   sh a sh b = ch(a + b) − ch(a − b) ;
                              2
                              1h                    i
                   sh a ch b = sh(a + b) + sh(a − b) .
                              2