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f
1
=
−−→
EA
1
|
−−→
EA
1
|
; f
2
=
−−−→
A
3
A
2
|
−−−→
A
3
A
2
|
.
−−→
EB
1
= |
−−→
EA
1
|(f
1
cos ϕ + f
2
sin ϕ)
−−→
EB
2
=
|
−−→
EA
1
|(f
1
cos(ϕ +
2π
3
) + f
2
sin(ϕ +
2π
3
))
−−→
EB
3
= |
−−→
EA
1
|(f
1
cos(ϕ −
2π
3
) + f
2
sin(ϕ −
2π
3
)) e
i
0
=
−−→
OE +
−−→
EB
i
ϕ =
π
3
−−→
EB
1
= −
−−→
EA
3
−−→
EB
2
= −
−−→
EA
1
−−→
EB
3
= −
−−→
EA
2
(A
3
EB
1
) = (A
1
EB
2
) = (A
2
EB
3
) = −2
B
1
B
2
B
3
e
1
0
=
−−→
OB
1
= {
2
3
;
2
3
; −
1
3
}
e
2
0
=
−−→
OB
2
= {−
1
3
;
2
3
;
2
3
} e
3
0
=
−−→
OB
3
= {
2
3
; −
1
3
;
2
3
}
x
1
x
2
x
3
=
2
3
−
1
3
2
3
2
3
2
3
−
1
3
−
1
3
2
3
2
3
x
1
0
x
2
0
x
3
0
.
{O; e
i
}
{O
0
; e
i
0
}
e
i
=
−−→
OA
i
e
i
0
=
−−→
O
0
A
i
i = 1, 2, 3 O 6= O
0
O
A
1
A
3
O
0
E
A
2
E
A
1
A
2
A
3
(
1
3
;
1
3
;
1
3
) O
0
OE
−−→
OO
0
= 2
−−→
OE
O
0
(
2
3
;
2
3
;
2
3
)
e
1
0
=
−−−→
O
0
A
1
= {
1
3
; −
2
3
; −
2
3
}
e
2
0
=
−−−→
O
0
A
2
= {−
2
3
;
1
3
; −
2
3
} e
3
0
=
−−−→
O
0
A
3
=
{−
2
3
; −
2
3
;
1
3
}
x
1
x
2
x
3
=
1
3
−
2
3
−
2
3
−
2
3
1
3
−
2
3
−
2
3
−
2
3
1
3
x
1
0
x
2
0
x
3
0
+
2
3
2
3
2
3
.
).+2+D +2++4+90D *0:-O 0,4)O −−→ −−−→ EA1 A3 A2 f1 = −−→ ; f2 = −−−→ . |EA1 | |A3 A2 | ),)7 1).+ 0E+C32-3 9).2+ − EB1 = |EA1 |(f1 cos ϕ + f2 sin ϕ) O EB2 = −→ −−→ −−→ −−→ 2π O −−→ −−→ |EA1 |(f1 cos(ϕ + 2π ) + f sin(ϕ + )) EB = |EA1 |(f1 cos(ϕ − 2π 3 ) + f2 sin(ϕ − 2π O :02)4 9).2+ 3 2 −− → 3 −− → +9++ 3 *0:-0 3 )) ei0 = OE + EBi 0--4+24 ,+C+*+ -1(0D ϕ = π 2+4 -1(0) − EB1 = −EA3 O −→ −−→ EB2 = −EA1 O EB3 = −EA2 O +2-AC0 0E+C4 ,+-2) +2+@)3 -4 −−→ −−→ −−→ −−→ 3 ª« O ®< (A3EB1) = (A1EB2) = (A2EB3) = −2 O 0 :02)4 .++C02 2+(). B1 O B2 B3 ?+-1) 9(-1)D ,+1(0)4 e10 = − OB1 = { 23 ; 32 ; − 31 } O −→ e20 = OB2 = {− 31 ; 23 ; 32 } O e30 = OB3 = { 32 ; − 13 ; 32 } O ,+2+4 F+41 ,)+*B −−→ −−→ 0:+903 .++C02 4)A2 9C~ 2 x 1 3 − 13 2 3 x 10 2 2 2 20 x = 3 3 − 13 x . − 31 2 2 0 x3 x3 ninn Î' +-20927 F+41 ,)+*0:+903 .++C02 , ,))E+B 3 3 C) +2 +2++4+90++ ),)0 {O; ei} . +2++4+90+4 ),) ( {O0 ; ei } O )-1 :9)-2+O 2+ ei = OAi O ei = O0 Ai O i = 1, 2, 3 O 0 O 6= O0 −−→ −−→ %ffMLf' 4 -+. 0--4+24O 0 0 O0 .0. 9 ,)CC )D :0C0()O 2+(. E O 3913A A-3 )2+4 ,0917++ 2)B +17.0 A1A2A3 20 2+(.0 4))2 .+B E Û ( ( +C02 ( 1 ; 1 ; 1 ) -+O 2+ 2+ .0 O0 1)B A1 A3 s2 0 ,34+D OE − OO0 = 2OE O ,+2+B 3 3 3 −→ −−→ 4 2+(.0 O0 4))2 .++C02 ( 2 ; 2 ; 2 ) A2 1)C+902)17+O e = − O A1 = { 3 ; − 23 ; − 23 } O −0−→ 1 3 3 3 O - 10 e2 = O0 A2 = {− 32 ; 13 ; − 23 } O e3 = O0 A3 = −−−→ −−−→ {− 2 ; − 2 ; 1 } O 0 ,)+*0:+90) .++C02 4))2 9C 0 0 3 3 3 0 1 2 2 2 x1 3 − 3 − 3 x1 3 2 2 1 2 20 2 x = −3 3 − 3 x + 3 . − 23 − 23 1 2 0 x3 3 x3 3 ×
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