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3
◦
[λb + µc, a] = λ[b, a] + µ[c, a]
1
◦
a||b [a, b] = 0 = −[b, a] a b
c = [a, b] d = [b, a] 2
∗
3
∗
d = ±c 4
∗
{a, b, c}
{a, b, c} {b, a, c} {b, a, −c}
0 1 0
1 0 0
0 0 1
0 1 0
1 0 0
0 0 −1
.
{b, a, −c} 1
◦
3
◦
1
◦
2
◦
2
◦
Ψ
a
= [a, ·] : E
3
3 b 7→ [a, b] ∈ E
3
a ∈ E
3
a = 0 2
◦
a 6= 0
λ 6= 0
[λa, b] = λ[a, b].
λ = 0
λ 6= 0 a||b
a b [a, b] = c [λa, b] = d 2
∗
3
∗
d||c |d| = |λ||c| d = ±λc
{a, b, c} {λa, b, λc}
λ 0 0
0 1 0
0 0 λ
= λ
2
> 0.
e
a
a a = |a|e
a
[a, b] = |a|[e
a
, b].
3◦ [λb + µc, a] = λ[b, a] + µ[c, a] ½hjnonqf¾pqkh' ? ( 1◦ -1 a||b O 2+ [a, b] = 0 = −[b, a] )C,+1+s4 2),)7O 2+ a b ) .+11)0O c = [a, b] O 0 d = [b, a] : -9+D-29 2∗ 3∗ -1)C)2O (2+ ( d = ±c : 4∗ -1)C)2O 2+ {a, b, c} ; ,09D *0:- 02 ,))E+C0 +2 {a, b, c} . {b, a, c} {b, a, −c} 4)A2O -++29)2-29)+O 9C 0 1 0 0 1 0 1 0 0 1 0 0 . 0 0 1 0 0 −1 ,)C)12)17 ,)9+D 402 +202)1)O 0 92++D ; ,+1+s2)1)O ,+B 2+4 ,094 3913)2-3 *0:- {b, a, −c} O (2+ C+.0:90)2 -9+D-29+ 1◦ 9+D-29+ 3◦ 92).0)2 : -9+D-29 1◦ 2◦ +.0s)4 2◦ 2+ -9+D-29+ +:0(0)2O (2+ +2+*0s)) Ψa = [a, ·] : E3 3 b 7→ [a, b] ∈ E3 1)D+ , 1A*+4 a ∈ E3 ? a = 0 -9+D-29+ 2◦ 9,+13)2-3 +()9CB 4 +*0:+4 01)) ,)C,+100)4O (2+ a 6= 0 ?+9)C)4 C+.0:02)17-29+ 9 )-.+17.+ @0+9 +.0s)4 -0(010O (2+ , λ 6= 0 9,+13)2-3 [λa, b] = λ[a, b]. ++2+@)) +()9C+ 9,+13)2-3 , λ = 0 O + + 0- 2))-)2 -1(0D λ 6= 0 ? a||b -++2+@)) 9,+13)2-3 +()9C4 +*0:+4 ?-27 9).2+ a b ) .+11)0 [a, b] = c O [λa, b] = d : 2∗ 3∗ -1)C)2O (2+ d||c |d| = |λ||c| O ,+2+4 d = ±λc -20)2-3 ,+9)27O (2+ *0:- {a, b, c} {λa, b, λc} +C0.+9+ +)2+90 + 2+ -1)C)2 : 2++O (2+ λ 0 0 0 1 0 = λ2 > 0. 0 0 λ ?-27 e ; )C(D 9).2+O 4)A D 2+ s) 0,091))O (2+ 9).B 2+ a O 2+ )-27O a = |a|ea O 2+C0 : -1)C)2O (2+ a [a, b] = |a|[ea , b]. ×
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